By Professor Meyer B. Jackson
Delivering complicated undergraduate and graduate scholars with a starting place within the easy ideas of biophysics, scholars who've taken actual chemistry and calculus classes will locate this e-book an available and priceless relief in studying how those thoughts can be utilized in organic study. The textual content offers a rigorous therapy of the basic theories in biophysics and illustrates their software with examples together with protein folding, enzyme catalysis and ion channel permeation. via those examples, scholars will achieve an realizing of the final significance and huge applicability of biophysical ideas to organic difficulties.
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Additional info for Molecular and Cellular Biophysics
30) gives 0 ½AA ½AB ½BA þ þ þ1 Po ¼ 1 ½BB ½BB ½BB 1 ¼ o o 1 þ 2eðÁGvi þ VÞ=RT þ e2ðÁGvi þ VÞ=RT (1:32) Note that [BB]/[AA] ¼ [AB]/[AA] times [BB]/[AB] from Eq. 30). The denominator of Eq. 32) is a complete square, so Po ¼ À 1 1 þ eðÁGvi o Á þ VÞ=RT 2 ¼ 1 2 ð1 þ eðV À V0 Þ=Vs Þ (1:33) The replacement of Gvio and by V0 and Vs involves the same notation used to go from Eq. 27) to Eq. 28). 33) is plotted together with Eq. 28) to illustrate how the interaction between the two subunits influences the shape of the transition (Fig.
4) can be used to estimate the free energy of placing an ion in a solvent with a particular dielectric constant. In the case of water this is the hydration energy. Data on the enthalpy of hydration provide a test for the picture of hydration as a polarization of the surrounding water. To obtain the enthalpy from Eq. 4) one differentiates with respect to temperature to obtain ÀS, as illustrated in the preceding section, and obtains H as G þ TS. The result is still an inverse dependence on r, and experimental data shown in Fig.
We can then solve for the force constant as b ¼ 100RT (1:40) Making this substitution, we can focus on the exponent in Eq. 38) and compare the linear and quadratic terms. qV À ðqVÞ2 ðqVÞ2 ¼ qV À 2b 200RT (1:41) Since RT/q $ 25 mV at room temperature for a unitary charge, we can further simplify this expression. qV À q qV 2 qV 2 ¼ qV À RT 200 5 volts (1:42) Now factoring out qV gives qVð À V=ð5 voltsÞÞ (1:43) When the dimensionless quantity V/(5 volts) is comparable to (which is also dimensionless because it is normalized to the thickness of the membrane) the V2 term will have an impact.
Molecular and Cellular Biophysics by Professor Meyer B. Jackson